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What is the probability that among 6 randomly selected grads, at least 1 finds a job in their chosen field?

A study conducted at a certain college shows that 64% of the school's graduates find a job in their field within a year after graduation.

Public Comments

1. If U knew the answer why'd you ask the question?
2. yes, why did you ask?
3. about 6 to 1
4. To figure this out we need to figure out what the probability is that none of them finds a job. There is a 36% chance that each of them does not find a job. So we need to take: .36 * .36 * .36 * .36 * .36 * .36 aka 36^6 which equals 0.00217678. That is the chance that none of them finds a job. So the chance that at least 1 of them finds a job is: 100-0.00217678= 99.9978%
5. The Binomial distribution has the probability function P(x=r)= nCr p^r (1-p)^(n-r) r=0,1,2,.....,n where nCr = n! / r! (n-r)! n=6 r=1,2,3,4,5,6 p=0.64 It is easier to compute the probability that 0 students found jobs and subtract it from 1. This is the same as at least 1 found a job. 1 - (6C0) (0.64)^0 (0.36)^6 =1-(0.36)^6 =1-0.002177 =0.9978